a numer is as much greater …
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Sia ? 6 years, 4 months ago
Let the number be <m:omath><m:r>x</m:r></m:omath>
From the problem it is understood that it is greater than 21 and less than 71.<m:omath><m:r>
x</m:r></m:omath> is greater than 21 by <m:omath><m:r>x</m:r></m:omath> - 21 and <m:omath><m:r>
x</m:r></m:omath> is less than 71 by 71 – <m:omath><m:r>x</m:r></m:omath>
According to the problem, <m:omath><m:r>x </m:r><m:r>-</m:r></m:omath> 21 = 71 – <m:omath><m:r>x</m:r></m:omath><m:omath><m:r>
x </m:r><m:r>+ </m:r><m:r>x</m:r></m:omath> = 71+21
2<m:omath><m:r>x</m:r></m:omath> = 92
{tex}x = \frac{{92}}{2} = 46{/tex}
Hence the required number is 46.
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