Let two consecutive positive integers =x,x+1 Product of two consecutive integers=306 X(x+1)=306 X square+x-306=0 By quadratic formula -b+-√d\2a -1+-√1-4(1)(-306)/2 -1+-√1225/2 -1+-35/2 X=-1+35/2=34/2=17 Or x=-36/2=-18 So x=17 So two consecutive positive integers=17and17+1=18

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