Tan3xtan2xtanx=tan3x-tan2x-tanx show that

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Sia ? 6 years, 4 months ago
From 3x = 2x + x
Applying tan on both sides..
tan3x = tan (2x+x)
tan3x = (tan2x+tanx)/1-tan2x tanx
(1-tan2x tanx)tan3x = tan2x+tanx
tan3x - tanx tan2x tan3x = tan2x+tanx
tanx tan2x tan3x = tan3x-tan2x-tanx
Hence it is proved.
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