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Find the area of a triangle …

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Find the area of a triangle having sodes of length 15cm,28cm,41cm. Also,find the length of altitude drawn from opposite vertex to the side of length 28cm.

Posted by Vaibhav Singh Gaur 5 years, 3 months ago

CBSE > Class 09 > Mathematics

2 answers

Mohd Raza 5 years, 3 months ago

15+28+42=85 not 84

0Thank You

Raj Kumar 5 years, 3 months ago

Given , a=15 , b=28 , c=41 Semiperimetre = 15+28+42/2 = 84/2 = 42 Area = √s(s-a)(s-b)(s-c) A=√42(42-15)(42-28)(42-41) A=√42×27×14×1 A=√2×3×7×1×3×3×3×1×2×7×1×1 A=2×3×7×3×1×1 A=126 cm*2

2Thank You

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CBSE > Class 09 > Mathematics