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If the following situation possible?if so determine their present ages.the sum of the ages of two friends is 20 year .four years ago ,the product of their ages isyears was 48

Posted by Kushal Kadyan 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

Let the present age of one friend be x years.

Also, sum of ages of both friends = 20 years

hence age of 2nd friend will be (20 - x) years.

4 years ago, age of 1st friend = (x - 4 ) years.
age of 2nd friend= (20-x)- 4 = (16-x) years.

According to the question;
(x - 4 )( 1 6 - x ) = 48

{tex}\Rightarrow{/tex} x² - 20x + 112 = 0
Let D be the discriminant of this quadratic. Then,
D ={tex}b^2-4ac{/tex} = 400 - 448 = -48 < 0. (here, a=1 b=-20, c=112)
So, above equation does not have real roots. Hence, the given situation is not possible.

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