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Sin18°/cos72° evaluate this.

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Sin18°/cos72° evaluate this.

Posted by Suniksha Bhatia 6 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Sia ? 6 years, 4 months ago

Sin 18/cos72 cos(90-72)/cos72
Cos72/sin72=1
Tan26/tan(90-74)=1
Cos48-sin42=sin(90-42)-sin42=0
Cosec31-Cosec(90-69) Cose31-Cosec31=0

0Thank You

Tanisha Yadav 6 years, 4 months ago

Sin theata = cos (90 - theata) So, Sin 18° =cos (90°- 18°) =cos 72° Cos 72°/cos72° =1

2Thank You

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