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Simply: (16-1/5)5/2

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Simply: (16-1/5)5/2

Posted by Kajal Singh 6 years, 4 months ago

CBSE > Class 09 > Mathematics

2 answers

Sia ? 6 years, 4 months ago

We have,
{tex}\left(16^{-\frac{1}{5}}\right)^{\frac{5}{2}}{/tex} = {tex}16^{-\frac{1}{5} \times \frac{5}{2}}{/tex} [as (a^m)ⁿ= a^m×n]
= {tex}16^{-\frac{1}{2}}{/tex}
= {tex}\frac{1}{16^{\frac{1}{2}}}{/tex}
= {tex}\frac{1}{\left(4^{2}\right)^{\frac{1}{2}}}{/tex}
= {tex}\frac{1}{4}{/tex}.

1Thank You

Muskan Agrawal 6 years, 4 months ago

(16-1/5)5/2 (80/5-1/5)5/2 79/5×5/2 =79/2

1Thank You

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