Simply: (16-1/5)5/2
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Sia ? 5 years, 3 months ago
We have,
{tex}\left(16^{-\frac{1}{5}}\right)^{\frac{5}{2}}{/tex} = {tex}16^{-\frac{1}{5} \times \frac{5}{2}}{/tex} [as (am)n= am×n ]
= {tex}16^{-\frac{1}{2}}{/tex}
= {tex}\frac{1}{16^{\frac{1}{2}}}{/tex}
= {tex}\frac{1}{\left(4^{2}\right)^{\frac{1}{2}}}{/tex}
= {tex}\frac{1}{4}{/tex}.
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