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Find 2 consecutive numbers whose square …

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Find 2 consecutive numbers whose square have the sum 85.

    • Posted by ?Harshitha? Harshi 6 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    ?Harshitha? Harshi 6 years, 4 months ago

    Yaa it is correct even i am getting the same answer

    0Thank You

    Madan M 6 years, 4 months ago

    Let two consecutive number is x and( x+1) x^2 +(x+1)^2=85 x^2+x^2+2x+1=85 2x^2+2x=85-1 2x^2+2x=84 2(x^2+x)=84 x^2+x=42 x^2+x-42=0 x^2-6x+7x-42=0 x(x-6)7(x-6)=0 (x-6)(x+7)=0 x=6,-7 If x is 6 then the other number (x+1) is 7 and if x=-7 then the other number ( x+1) is -6. Prove : x=6 (6)^2+(7)^2=36+49=85 x=-7 ( -7)^2 +(-6)^2 = 49+36=85 Hence the two numbers are 6 and 7

    1Thank You

    Abhay Yadav 6 years, 4 months ago

    My Answer is 6 and. 7 If it is right Answer then you reply me

    1Thank You

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