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√5-3i =

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√5-3i =
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Ayush Vishwakarma?? 6 years, 4 months ago

Dekh simple hai. Let inverse multiplicity of root 5-3i = 1/root5-3i. 1/root5-3i=root5+3i/root5+3i. Root5+3i/square of root5-square of 3i = root5+3i/5+9 then root5/14+3i/14. Value of i^2=-1.
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