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If the point (2k-3)(k+2)lies on the …

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If the point (2k-3)(k+2)lies on the graph of equation 2k+3y+15=0 find the value of k

Posted by Priya Seth 5 years, 3 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 5 years, 3 months ago

According to the question, given equation is {tex} 2x + 3y + 15 = 0.{/tex}
So, putting x = 2k - 3 and y = k + 2 in equation, we get
{tex}\Rightarrow{/tex} {tex}2(2k - 3) + 3(k + 2) +15 = 0{/tex}
{tex}\Rightarrow{/tex} {tex}4k - 6+ 3k + 6 + 15 = 0{/tex}
{tex}\Rightarrow{/tex} {tex}7k + 15 = 0{/tex}
{tex} \Rightarrow 7 k=-15 \\ \Rightarrow \ k=-\frac{15}{7}{/tex}

1Thank You

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CBSE > Class 09 > Mathematics