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If a wire is stretched to …

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If a wire is stretched to ‘n’ times its original length how does the R change? On stretching, volume remains constant.

Posted by Ďãřşháñăã Yadav ? ? ? 6 years, 2 months ago

CBSE > Class 12 > Physics

9 answers

Aastha Saxena 6 years, 2 months ago

R will become 2 times more ...for example when length is n times raised then resistance will be n*2

Ďãřşháñăã Yadav ? ? ? 6 years, 2 months ago

thx

Rajat Barwar 6 years, 2 months ago

It will become n^2 times. Wire length will become n times and by keeping volume same,its new area will be 1/n times the initial area of cross section... now by applying formula of resistance you will get the answer... Hope it may help you...

Ďãřşháñăã Yadav ? ? ? 6 years, 2 months ago

thx divya. ?

Divya Deep Srivastava 6 years, 2 months ago

We get n^2.

Divya Deep Srivastava 6 years, 2 months ago

R is directly proportional to L/A. Now,we R=L*L/A*l=L^2/volume. Now,we compare initial and final R as follows-R1/R2=L1^2/L2^2,volume got cancelled being equal. R1=initial R R2=Final R L1=initial L L2=final L. L1=L,L2=nL Now putting the value of L1 and L2 in eqation,we get R1/R2= L^2/(nL)^2 So,we get R2=n=2. This is the perfect answer. I hope you will understand this expalnation.

Ďãřşháñăã Yadav ? ? ? 6 years, 2 months ago

thx once again

Ďãřşháñăã Yadav ? ? ? 6 years, 2 months ago

format bta do answer ka. ? ? ?

Ďãřşháñăã Yadav ? ? ? 6 years, 2 months ago

yes

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