Trigonometry: In a right-angled triangle, the …

SinA 0°=0 30°=1/2 45°=1/√2 60°=√3/2 90°=1 we have learn only sin A value and all value learn eaisly cosA value opposite to sin A all value like cosA 0°=1 30°=√3/2 45° = 1/√2 60°= 1/2 90°=0 tanA all ratio find use sinA/cosAformula like tanA0°=sin0°/cos0° 0/1 = 0 so tanA0° is 0 similarly all tanA trignometric ratio find sinA/cosA tanA 30° = sin30°/cos30° 1/2/√3/2 = 1√3 tanA 45°= sin 45°/cos45°=1/√2/1/√2 = 1 tanA 60° = sin60°/cos60°=√3/2/1/2=√3 tanA 90°= sin90°/cos90° =1/0 = not define means soch ke bhar find cosecA trigonometric ratio use 1/sinA like cosecA 0° = 1/sin0°= 1/0= not define cosecA 30°= 1/sin30°=1/1/2=2 cosecA 45°=1/sin45°=1/1√2= √2 cosec60°=1/sin60°= 1/√3/2= 2/√3 cosec90°=1/sin90°= 1/1 = 1 secA opposite to cosecA like secA 0°= cosecA 90° secA 0°=1 secA 30°= cosecA 60° sec 30°= 2/√3 sec45°=cosec45° sec45°= √2 secA 60°= cosecA 30° secA 60°= 2 secA 90°= cosecA 0° sec90°= not define agr app iss mai confuse ho rhe ho to app ko yaad hoga sinA ka opposite cosecA hota h cosA ka opposite secA hota h hum cosA ko 1/secA likh skte h aise hi secA ko 1/cosA likh skte h 1/cosA ki value agr lagyege to hume secA ke all trignometric ratio pta chl jayege ab bacha cotA bhut easy h isme hum cosA/ sin A lga kar kr skte h ya fir 1/tanA lga kr . Isse hum easily yaad kr skte h sare ratio frnds bs hume sinA ke all trigonometric ratio yad hone chaiye baki hum formula lga kr skre kr skte h.????