If tan alpha =5/12 find the …

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Sia ? 6 years, 3 months ago
According to the question, tan {tex}\alpha{/tex} = {tex}\frac{5}{12}{/tex}
We know that, sec {tex}\alpha{/tex} = {tex}\sqrt{1 + tan^2 \alpha}{/tex}
= {tex}\sqrt{1 + \frac{25}{144}}{/tex}
={tex}\sqrt{ \frac{144+25}{144}}{/tex}
={tex}\sqrt{ \frac{169}{144}}{/tex}
= {tex}\frac{13}{12}{/tex}
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