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Tan^2thita -sin^2thita =tan^2thita×sin^2thita

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Tan^2thita -sin^2thita =tan^2thita×sin^2thita

Posted by Alisha Vir 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Harsh Mishra 6 years, 4 months ago

If you mean, to prove (tan²θ - sin²θ) = tan²θ × sin²θ , then the answer will Be.....

L.H.S = tan²θ - sin²θ

= sin²θ/cos²θ - sin²θ

= sin²θ [ 1/cos²θ - 1]

[ we know, sec x = 1/cos x so, 1/cos²θ = sec²θ]

= sin²θ [ sec²θ - 1]

we also know that, sec² x - tan² x=1

so,sec² θ - tan² θ=1

or,sec² θ - 1 = tan² θ

then, sin² θ [sec²θ - 1] = sin² θ × tan² θ = RHS

Hence, (tan² θ - sin² θ) = tan² θ × sin² θ.

0Thank You

ANSWER

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