calculate angular velocity of hand clock?
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Posted by Adarsh Singh 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
Therefore, Angular velocity of the hour hand of a clock, {tex}\omega=\frac{2 \pi}{T}=\frac{2 \times 3.14}{12 \times 60 \times 60}{/tex}= 1.45 {tex}\times{/tex} 10-4 rad s-1
Therefore, Angular velocity of the second hand of a clock {tex}\omega=\frac{2 \pi}{T}=\frac{2 \pi}{60}{/tex}= 0.105 rad s-1
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