Solve 2x + 3y = 11 …

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Sia ? 6 years, 4 months ago
2x +3y =11 ............... (1)
2x−4y =−24 ................ (2)
Using equation (2), we can say that
2x =−24 + 4y
⇒ x =−12 + 2y
Putting this in equation (1), we get
2(−12 + 2y )+3y =11 ⇒ −24 + 4y + 3y =11
⇒ 7y =35 ⇒ y =5
Putting value of y in equation (1), we get
2x +3(5)=11 ⇒ 2x +15=11
⇒ 2x =11 - 15=−4 ⇒ x =−2
Therefore, x =−and y =5
Putting values of x and y in y =mx +3, we get
5=m (−2) + 3 ⇒ 5 =−2m +3
⇒ −2m =2 ⇒ m =−1
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