If the product of zeros of …
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Sia ? 6 years, 4 months ago
According to the question,we have to find the value of a such that the product of the zeros of the polynomial (ax2 - 6x - 6) is 4.
Let {tex} \alpha{/tex} and {tex}\beta{/tex} be the zeros of the polynomial (ax2 - 6x - 6)
Then, {tex}\alpha{/tex}{tex} \beta{/tex} = {tex} \frac { \text { constant term } } { \text { coefficient of } x ^ { 2 } } = \frac { - 6 } { a }{/tex}
But, {tex} \alpha{/tex}{tex} \beta{/tex} = 4 (given).
{tex} \therefore \quad \frac { - 6 } { a } = 4 \Rightarrow 4 a = - 6 \Rightarrow a = \frac { - 6 } { 4 } = \frac { - 3 } { 2 }{/tex}
Hence, a = {tex} \frac { - 3 } { 2 }{/tex}
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