Proof that root 5 is an …
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Sia ? 5 years, 9 months ago
Let √5 is a rational number.
√5=ab(a, b are co-primes and b≠0)
or, a=b√5
On squaring both the sides, we get
a2=5b2 ---------------------------------(1)
Hence 5 is a factor of a2
so 5 is a factor of a
Let a = 5c, (c is some integer)
∴ a2 = 25c2
From equation(1) putting the value of a2
or, 5b2 = 25c2
or b2=5c2
so 5 is a factor of b2
or 5 is a factor of b
Hence 5 is a common factor of a and b
But this contradicts the fact that a and b are co-primes.
This is because we assumed that √5 is rational
∴ √5 is irrational.
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