Find the quadratic polynomial each with …

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Sia ? 6 years, 4 months ago
Let the polynomial be ax2 + bx + c,
and its zeroes be {tex}\alpha {/tex} and {tex}\beta {/tex}.
Then, {tex}\alpha + \beta = 0 = - \frac { b } { a } \text { and } Q \beta = \sqrt { 5 } = \frac { c } { a }{/tex}
If a = 1, then b = 0 and {tex}c = \sqrt { 5 }{/tex}.
So, one quadratic polynomial which fits the given conditions is {tex}x ^ { 2 } + \sqrt { 5 }{/tex} .
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