Prove that sqrt 5 is irrational

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Sia ? 6 years, 4 months ago
Let take √5 as a rational number
If a and b are two co-prime number and b is not equal to 0.
We can write √5 = a/b
Multiply by b both side we get
b√5 = a
To remove root, Squaring on both sides, we get
5b2 = a2 ……………(1)
Therefore, 5 divides a2 and according to a theorem of rational number, for any prime number p which is divided 'a2' then it will divide 'a' also.
That means 5 will divide 'a'. So we can write
a = 5c
and putting the value of a in equation (1) we get
5b2 = (5c)2
5b2 = 25c2
Divide by 25 we get
b2/5 = c2
again using the same theorem we get that b will divide by 5
and we have already get that a is divided by 5
but a and b are co-prime number. so it is contradicting.
Hence √5 is an irrational number
1Thank You