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Sin(B+C/2)=cos(A/2). Prove

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Sin(B+C/2)=cos(A/2). Prove

Posted by Sawani Belhe 6 years, 5 months ago

CBSE > Class 10 > Mathematics

3 answers

Piyush Raj 6 years, 5 months ago

A+B+C/2=180/2 B+C/2=90=-A/2 B+C/2=90-A/2 multiplying both sides by sinA we get sin(B+C/2)=sin(90-A/2) sin(B+C/2)=cos(A/2) hence it is proved

Piyush Raj 6 years, 5 months ago

A+B+C/2=180/2

Priyanjali Singh 6 years, 5 months ago

In triangle abc A+B+C=180 dividing both side by 2 A/2 +B/2+c/2=90 b/2+c/2=90-a/2 sin(b+c/2)=sin(90-a/2) sin(b+c/2)=cot(a/2)

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