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Co ordinator geometry find the ratio …

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Co ordinator geometry find the ratio in which the line segment joining the point (-3,10)and (6,-8)is divided by (-1,6)

    • Posted by Pushpa Keerthi 6 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 5 months ago

    Let (-1, 6) divides line segment joining the points (-3, 10) and(6, -8) in k:1.
    Using Section formula, we get
    {tex} - 1 = \frac{{( - 3) \times 1 + 6 \times k}}{{k + 1}}{/tex} {tex}4 \Rightarrow - k - 1 = ( - 3 + 6k){/tex}
    ⇒ −7k = −2 ⇒ k= {tex}\frac{2}{7}{/tex}
    Therefore, the ratio is {tex}\frac{2}{7}:1{/tex} which is equivalent to 2:7.
    Therefore, (-1, 6) divides line segment joining the points (-3, 10) and (6, -8) in 2:7.

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