An exterior angle of a triangle …
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Posted by Hariom Dalal 5 years, 10 months ago
- 2 answers
Srishtika Murugan 5 years, 10 months ago
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Sia ? 5 years, 10 months ago
Let in △ABC, exterior ∠ACE = 115o and ∠A = 35o

We know that,
∠ACE = ∠A + ∠B (Exterior Angle Theorem)
⇒ 115o = 35o + ∠B
∠B = 115o – 35o = 80o
Again, in △ABC,
∠A + ∠B + ∠C = 180o
(The sum of the three angles of a triangle is 180o)
⇒ 35o + 80o + ∠C = 180o
⇒ 115o + ∠C = 180o
⇒ ∠C = 180o – 115o = 65o
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