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Find two consecutive multiples of 3 …

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Find two consecutive multiples of 3 whose products is 648.

Posted by Nazish Parween 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 5 months ago

Let two consecutive multiples of 3 be x and (x+3)

As per given condition

x (x+3) = 648

⇒ x² + 3x = 648

⇒ x² + 3x -648 = 0

⇒ x² + 27x - 24x -648 = 0

⇒ x ( x + 27 ) -24 ( x +27)

⇒ ( x - 24) ( x + 27)

⇒ x = 24 and x = -27

so, we take x = 24.

Required multiples of 3

⇒ x = 24

⇒ x +3 = 24+3 = 27.

1Thank You

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