Solve for 'x' and 'y' 7(y+3)-2(x+2)=14 …
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Sia ? 6 years, 5 months ago
The given equations are:
7(y + 3) - 2(x + 2) = 14
4(y - 2) + 3(x - 3) = 2
So, 7(y + 3) - 2(x + 2) = 14
⇒ 7y + 21 - 2x - 4 = 14
⇒ 7y - 2x = 14 + 4 - 21
⇒ - 2x + 7y = -3 ........ (i)
And 4(y - 2) + 3(x - 3) = 2
⇒ 4y - x + 3x - 9 = 2
⇒ 4y + 3x = 2 + 8 + 9
⇒ 3x + 4y = 19 .............(ii)
Multiplying (i) by 4 and (ii) by 7, we get
-8x + 28y = -12........(iii)
21x + 28y = 133......(iv)
Subtracting (iii) and (iv),we get
29x = 145
x = 5
Substituting x = 5 in (i),we get
7y = -3 + 10
⇒ 7y = 7
⇒ y = 1
{tex}\therefore{/tex} Solution is x = 5, y = 1
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