Two capacitors of capacitance of 6 …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Two capacitors of capacitance of 6 micro farad and 12 micro farad are connected in series with a battery. The voltage across 6 micro farad capacitor is 2 volt . Compute the total battery voltage
Posted by Ani Verma 6 years, 5 months ago
- 3 answers
Lavanya ❤️? 6 years, 5 months ago
Charge on 6 uf capacitor will be equal to product of capacitance and potential difference.
= 6uf×2v
=12 u coulombs
there fore charge on 12uf capacitor will be equal 12 u coulombs. And potential difference across it will be
= capacitance = charge ÷ potential difference
therefore,
v = q÷c
v= 12 u c ÷ 12 uf
v = 1 volt
therefore total potential difference is
= 2v + 1v
= 3v
Test
Related Questions
Posted by Anterpreet Kaur 1 year, 5 months ago
- 0 answers
Posted by Aniket Mahajan 10 months ago
- 0 answers
Posted by Khushbu Otti 1 year, 5 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Nishu Sahu 6 years, 5 months ago
0Thank You