Solve using suitable properties : -2/3 …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Upakshi Dutta Baruah 6 years, 10 months ago
- 1 answers
Related Questions
Posted by Shara Ravindran 18 hours ago
- 0 answers
Posted by Priyanshu Kushwaha 4 hours ago
- 1 answers
Posted by Shubham Yadav 3 days, 3 hours ago
- 0 answers
Posted by Arshad Khan 3 days, 19 hours ago
- 2 answers
Posted by Saanvi Juneja 1 day ago
- 0 answers
Posted by Aditya Pranav 4 days, 22 hours ago
- 0 answers
Posted by Priyanshu Kushwaha 4 hours ago
- 0 answers
Posted by Tahir Khan 4 days, 18 hours ago
- 0 answers
Posted by Nancy Kumari 3 days, 8 hours ago
- 0 answers
Posted by Anshi Sharma 1 day, 21 hours ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Payal Singh 6 years, 10 months ago
{tex}-{2\over 3} \times {3\over 5} +{5\over 2}-{3\over 5} \times {1\over 6}{/tex}
= {tex}-{2\over 3} \times {3\over 5}-{3\over 5} \times {1\over 6} +{5\over 2} {/tex}
Using distributive property of multiplication,
{tex}= {3\over 5}\times \left ( -{2\over 3}-{1\over 6}\right ) +{5\over 2} {/tex}
{tex}= {3\over 5}\times \left ({ -4-1\over 6}\right ) +{5\over 2} {/tex}
{tex}= {3\over 5}\times { -5\over 6} +{5\over 2} {/tex}
= {tex}-{1\over 2} + {5\over 2}{/tex}
{tex}= {-1+5\over 2} = {4\over 2}{/tex}
= 2
1Thank You