The sum of digits of a …
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Payal Singh 8 years, 1 month ago
Let ones place digit = x
Tens place digit = y
Then number = 10y+x
After interchanging digit,
Ones place digit = y
Tens place digit = x
Then new number = 10x+y
According to question
x+y = 11 ......(1)
Also
=> 10x+y = 10y+x+63
=> 9x-9y = 63
=> x-y = 7 .....(2)
Add (1) and (2)
=> 2x = 18
=> x = 9
From (2)
=> 9-y = 7
=> y = 2
So number is = 10*2+9 = 29
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