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AP 3‚15‚27‚39… will be 120 more …

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AP 3‚15‚27‚39… will be 120 more than its 21st term.

Posted by Vashu Jaiswal 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Here we are having a=3
and d=15-3=12
Let nth term T_n =T₂₁+120
so a+(n-1)d = a+20d+120
or (n-1){tex}\times{/tex}12 = 20 {tex}\times{/tex} 12+120
12n -12 = 240+120
12n = 372
{tex}\style{font-size:12px}{\text{n=}\frac{372}{12}=31}{/tex}
Hence, 31st term is the required term.

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