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Two resistors of resistance R1=100+/-3 ohm …

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Two resistors of resistance R1=100+/-3 ohm and R2=200+/-4 ohm are connected (a) in series ,(b) in parallel.Find the equivalent resistance of the (a) series combination,(b) parallel combination .Use for (a) the relation R=R1+R2 and for (b) 1/R'=
  • 1 answers

Aditya Maurya 6 years, 5 months ago

For serious combination..r1+r2 =(100+-3)+200+/-4==(300+-7)ohm (B) 1/r1+1r2=1/100+-3)+(1/200+-4) =delR/R1+delR/R2=3/100+4/200 ==5/100==0.05ohm
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