A series has An =n×n +1is …

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Sia ? 6 years, 5 months ago
an = n2 - 1
Put n = 1, 2, 3, 4, ..... we get,
a1 = 12 - 1 = 1 - 1 = 0
a2 = 22 - 1 = 4 - 1 = 3
a3 = 32 - 1 = 9 - 1 = 8
a4 = 42 - 1 = 16 - 1 = 15, and so on.
Hence, the given sequence is 0, 3, 8, 15
a2 - a1 = 3 - 0 = 3
a3 - a2 = 8 - 3 = 5
As a2 - a1 {tex} \ne {/tex} a3 - a2, the given sequence is not an AP.
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