Find the zeros of the following …

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Sia ? 6 years, 5 months ago
The given polynomial
f(x)=6x2-7x-3
= (3x + 1)(2x - 3)
f(x)=0 if 3x+1=0 or 2x-3=0
So zeros of the polynomials are {tex}\frac{3}{2}{/tex} and {tex}\frac{{ - 1}}{3}{/tex}
In f(x)=6x2-7x-3
Sum of the zero= {tex}\frac32-\frac13=\frac76=-\frac{\mathrm b}{\mathrm a}{/tex}
Product of zeros = {tex}\frac32\times-\frac13=-\frac12=\frac{\mathrm c}{\mathrm a}{/tex}
Hence, the relationship is verified.
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