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if Q=(A^2*B^3/2)/C^4*D^1/2 ;and percentage error in …

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if Q=(A^2*B^3/2)/C^4*D^1/2 ;and percentage error in A is 1%,Bis 2%,C is 4% and Dis 2%then find percentage error in Q

  • 2 answers

Akshat Vashishth 8 years, 2 months ago

2*1%+3/2*2%+4*4%+1/2*2%=22%

Arshika Vishwakarma 8 years, 2 months ago

= 2×1% + 3/2×2% + 4×4% + 1/2×2% = 2/100 +3/100+16/100+1/100 = 22/100×100 = 22%
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