Five years hence the age of …
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Sia ? 6 years, 5 months ago
Let x (in years) be the present age of Jacob's son and y (in years) be the present age of Jacob. 5 years hence, it has relation:
(y + 5) = 3(x + 5)
or, y + 5 = 3x + 15
3x + 15 - y - 5 = 0
or, 3 x - y + 10 = 0 .......(i)
5 years ago, it has relation
(y - 5) = 7(x - 5)
y - 5 = 7x - 35
or, 7x - 35 - y + 5 = 0
or, 7 x - y - 3 0 = 0 ....(ii)
From eqn. (i), y = 3x + 10 ....(iii)
On substituting the value of y in eqn. (ii), we get
7x-(3x + 10) - 30 = 0
7x - 3x - 10 - 30 = 0
or, 4x - 40 = 0
or, 4x = 40
x=10
On substituting x = 10 in eqn. (iii),
{tex}y = 3 \times 10 + 10{/tex}
y = 30 + 10
{tex}\therefore {/tex} y = 40
Hence, the present age of Jacob = 40 years and son's age = 10 years
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