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a3-b3=

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a3-b3=
  • 4 answers

Darshan Darshan 6 years, 5 months ago

(a

Yogita Ingle 6 years, 5 months ago

a³ – b³ = (a – b)(a² + ab + b²)
you know that
(a – b)³ = a³ + 3ab(a – b) – b³
then a³ – b³ = (a – b)³ + 3ab(a – b)
= (a – b)[(a – b)² + 3ab]
= (a – b)(a² – 2ab + b² + 3ab)
= (a – b)(a² + ab + b² )

Adi Kumar Paswan 6 years, 5 months ago

3(a-b)

Neha Panchal 6 years, 5 months ago

(a-b)3 - 3ab(a-b)
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