If , x2+1/x2=27 Then, x+1/x=?

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Posted by Prabhati Acharya 8 years, 6 months ago
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Payal Singh 8 years, 6 months ago
Given : {tex}x^2+{1\over x^2}= 27{/tex}
We know,
{tex}(a+b)^2=a^2+b^2+2ab{/tex}
Put a = x and b={tex}{1\over x} {/tex}
We get
{tex}=> (x+{1\over x})^2 = x^2+{1\over x^2}+2\times x\times {1\over x}{/tex}
{tex}=> (x+{1\over x})^2 = 27+2=29{/tex}
{tex}=> x+{1\over x} =\pm \sqrt{29}{/tex}
0Thank You