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Iine L is the bisector of …

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Iine L is the bisector of an angle A and B is any point on L . BP and BQ are perpendiculars from B to the arms of A. Show that :(I) APB=AQB (Ii) BP=BQ or B is a equidistant from the arms of A
  • 1 answers

Sia ? 6 years, 5 months ago

  1. In DAPB and DAQB
    {tex}\angle{/tex}BAP = {tex}\angle{/tex}BAQ ...[As l bisects {tex}\angle{/tex}A]
    {tex}\angle{/tex}BPA = {tex}\angle{/tex}BQA ...[Each 90°]
    AB = AB ...[Common]
    {tex}\therefore{/tex} DAPB {tex}\cong{/tex} DAQB proved ...[AAS property] ...(1)
  2. DAPB {tex}\cong{/tex} DAQB ...[From (1)]
    {tex}\therefore{/tex} BP = BQ ...[c.p.c.t.]
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