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Evaluate ½√486 -√27/2

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Evaluate ½√486 -√27/2

Posted by Shaaz Fathima 8 years, 6 months ago

CBSE > Class 09 > Mathematics

1 answers

Poulami Dasgupta 8 years, 5 months ago

{tex}{1\over2}\sqrt{486}-{\sqrt{27}\over2}{/tex}

{tex}{1\over2}\sqrt{2\times3\times3\times3\times3\times3}{/tex}—{tex}\sqrt{3\times3\times3}\over2{/tex}

{tex}{1\over2}\times3\times3\sqrt{6}{/tex}—{tex}3\sqrt{3}\over2{/tex}

{tex}{9\sqrt{6}\over2}—{3\sqrt{3}\over2}{/tex}

{tex}9\sqrt{6}—3\sqrt{3}\over2{/tex}

{tex}3(3\sqrt{6}—\sqrt{3})\over2{/tex}

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