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If the error in measurement of …

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If the error in measurement of radius of sphere is 2%what will be percentage error in volume?

  • 2 answers

Akshat Vashishth 8 years, 2 months ago

Volume of sphere =4/3*22/7*r^3=3*2%=6%

Talha Sarfraz 8 years, 2 months ago

% error in radius of sphere =2%. volume of sphere =4/3×πr^3 ∆r/r=3×4/3×∆r/r ∆r/r×100=4[∆r/r×100] ∆r/r×100=4×2 ∆r/r×100=8%
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