If sec theta +tan theta =m; …

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Posted by Uallasgowda K R Uallasgowda K R 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
Given: (sec{tex}\theta{/tex} + tan{tex}\theta{/tex}) = m and (sec{tex}\theta{/tex} - tan{tex}\theta{/tex}) = n,
LHS = mn = (sec{tex}\theta{/tex} + tan{tex}\theta{/tex})(sec{tex}\theta{/tex} - tan{tex}\theta{/tex})
= sec2{tex}\theta{/tex} - tan2{tex}\theta{/tex} = 1 = RHS [{tex}\because{/tex} sec2{tex}\theta{/tex} - tan2{tex}\theta{/tex} = 1]
{tex}\therefore \sqrt {mn} = 1{/tex}
1Thank You