Consider the numbers 4n,where n is …

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Posted by Anusha_Devisetty Cherry 6 years, 5 months ago
- 2 answers
Sia ? 6 years, 5 months ago
If a number ends with zero then it is divisible by 5.
For unit’s digit to be 0, then 4n should have 2 and 5 as its prime factors, but 4n = (22)n = 22n.
As n {tex}\in{/tex} N we take n=1,2,3,4...etc
So above becomes 41,42 ...etc
As it does not contain 5 as one of its prime factors.
Therefore, 4n will not end with digit 0 for n {tex}\in{/tex} N.
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Shubham Pandey 6 years, 5 months ago
0Thank You