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Find the area of a triangle two side of which are 18cm and 10cm and the perimeter is 42 cm

Posted by Ziddi Rao Shabh. 5 years, 4 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 5 years, 4 months ago

Let a=18 cm, b=10 cm
Perimeter =42cm
{tex}\therefore a+b+c=42cm{/tex}
So, C=14 cm
{tex}\therefore \text{ S=}\frac{a+b+c}{2}\text{ =}\frac{18+10+14}{2}{/tex} = 21 cm
new area of triangles {tex}=\sqrt{21(21-18)\text{ (21}-\text{10) (21}-\text{14)}}\\ \text{= }\sqrt{21\times 3\times 11\times 7}{/tex}
{tex}\text{=21}\sqrt{11}\text{ }sq\text{ cm}{/tex}

1Thank You

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