A Right angle triangle has hypotenuse …

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Sia ? 6 years, 5 months ago
Let third side = x cm
Then by Pythagoras theorem,
p2 = q2 + x2
x2 = p2 - q2
= (p + q) ( p - q)
= (p + q) {tex} \times{/tex} 1 ( {tex}\because {/tex} p - q = 1)
= q + 1 + q
= 2q + 1
{tex}\therefore {/tex} x ={tex}\sqrt {2q + 1} {/tex}
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