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If x+y+z=0, then show that x^2+y^2+z^2=-2(xy+yz+zx)

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If x+y+z=0, then show that x^2+y^2+z^2=-2(xy+yz+zx)
  • 2 answers

Vansh Gupta 5 years, 4 months ago

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#Joel Wilson 5 years, 4 months ago

(x+y+z)²=0² x²+y²+z²+2xy+2yz+2zx=0 transpose 2xy+2yz+2zx to RHS x²+y²+z²= -(2xy+2yz+2zx) Take 2 common x²+y²+z²=-2(xy+yz+zx)
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