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In a triangle abc < c …

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In a triangle abc < c =3< b =2(<a+<b) Then find three angle
  • 1 answers

Mayank Sharma 6 years, 5 months ago

Let angle b be= x. So, angle c be 3x . angle a be x/2. A+B+c =180. X/2+x+3x = 180. X/2+4x=180.(do through out multiplication of 2 in eqn). X+8x=360. 9x=360. X =40. Putting the value of x in a and b and c. a= 40÷2=20. b = 40 . c= 40(3) = 120.
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