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SinA(1+tanA)+cosA(1+cotA)=secA+cosecA

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SinA(1+tanA)+cosA(1+cotA)=secA+cosecA

Posted by Shruti Khandelwal 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Mugdha Kumari 6 years, 5 months ago

SinA (1+sinA/cosA)+cosA(1+cos/sin). =sinA(cosA+sinA/cosA)+cos(sin+cos/sinA). =sinA+cosA(sin/cosA+cosA/sinA). =(SinA+cosA)(sin^2A+cos^2A/sinA×cosA). =sinA+cosA/sinA×cosA. =1/cosA+1/sinA. =secA+cosecA. Proved...

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