tan A ÷sec A-1+tan A ÷sec …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Md Abrarul Haque 6 years, 5 months ago
- 1 answers
Test
Related Questions
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
Posted by Kanika . 1 month ago
- 1 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 5 months ago
LHS = {tex}\frac{\tan A}{\sec A-1}+\frac{\tan A}{\sec A+1}{/tex}
{tex}=\frac{\tan A(\sec A+1)+\tan A(\sec A-1)}{(\sec A-1)(\sec A+1)}{/tex}
{tex}=\frac{\tan A \cdot \sec A+\tan A+\tan A \sec A-\tan A}{\sec ^{2} A-1}{/tex}
{tex}=\frac{2 \tan A \sec A}{\tan ^{2} A}{/tex} [{tex}\because{/tex} {tex}(sec^2\theta - 1) = tan^2\theta {/tex}]
{tex}=\frac{2 \sec A}{\tan A}{/tex}
{tex}=\frac{2 \frac{1}{\cos A}}{\frac{\sin A}{\cos A}}{/tex}
{tex}=2 \times \frac{1}{\cos A} \times \frac{\cos A}{\sin A}{/tex}
{tex}=\frac{2}{\sin \mathrm{A}}{/tex}
{tex}= 2 cosec\ A{/tex} = RHS
1Thank You