A metallic sphere of radius 4.2cm …
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Sia ? 6 years, 5 months ago
For sphere Radius (r) = 4.2 cm
{tex}\therefore{/tex} Volume = {tex}\frac{4}{3}{/tex}{tex}\pi{/tex}r3
= {tex}\frac{4}{3}\pi{/tex}(4.2)3 cm3
For cylinder Radius (R) = 6 cm
Let the height of the cylinder be H cm.
Then, volume = {tex}\pi{/tex}R2H = {tex}\pi{/tex}(6)2H cm3
According the question,
Volume of the sphere = Volume of the cylinder
{tex}\Rightarrow{/tex} {tex}\frac{4}{3} \pi(4.2)^{3}=\pi(6)^{2} \mathrm{H} \Rightarrow \mathrm{H}=\frac{4(4.2)^{3}}{3(6)^{2}} \Rightarrow 2.74{/tex}
Hence, the height of the cylinder is 2.74 cm.
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