Solve graphically the system of linear …
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Sia ? 6 years, 5 months ago
The given system of equation is {tex}4x - 3y + 4 = 0{/tex} and {tex}4x + 3y - 20 = 0{/tex}
Now, {tex}4x - 3y + 4 = 0{/tex}
{tex}x = \frac{{3y - 4}}{4}{/tex}
Solution table for {tex}4x - 3y + 4 = 0{/tex}
We have,
{tex}4x + 3y - 20 = 0{/tex}
{tex}x = \frac{{20 - 3y}}{4}{/tex}
Solution table for {tex}4x + 3y - 20 = 0{/tex}
Graph of the given system is:
Clearly, the two lines intersect at A(2, 4)
We also observe that the lines meet x - axis B(-1, 0) and C(5, 0)
Thus x = 2 and y = 4 is the solution of the given system of equations.
AD is drawn perpendicular A on x - axis. Clearly we have,
AD = y - coordinate point A(2, 4)
AD = 3 and BC = 5 - (-1) = 4 + 1 = 6
Area of the shaded region = {tex}\frac{1}{2}{/tex} × base × altitude
{tex} = \frac{1}{2} \times 6 \times 4{/tex}
= 12 sq. units
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