a³-8b³-64c³-24abc
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Yogita Ingle 5 years, 4 months ago
⇒a³-8b³-64c³+24abc
⇒ a³+(-2b)³+(-4c)³ -3 × a × (-2b) × (4c)
⇒ X³+Y³+Z³-3XYZ , where a = X , Y = (-2b) , Z = (-4c)
⇒ (X+Y+Z)(X²+Y²+Z²- XY- YZ- ZX)
⇒ [(a +(-2b) + (-4c) ] × [ a² + (-2b)² + (-4c)² -a (-2b)-(-2b) (-4c) -a(-4c) ]
⇒ (a-2b-4c)(a²+4b²+16c²+2ab-8bc+4ac).
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