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a³-8b³-64c³-24abc

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a³-8b³-64c³-24abc

    • Posted by Samarth Jain 6 years, 5 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Yogita Ingle 6 years, 5 months ago

    ⇒a³-8b³-64c³+24abc

    ⇒ a³+(-2b)³+(-4c)³ -3 × a × (-2b) × (4c)

    ⇒  X³+Y³+Z³-3XYZ , where a = X , Y = (-2b) , Z = (-4c)

    ⇒ (X+Y+Z)(X²+Y²+Z²- XY- YZ- ZX)

    ⇒ [(a +(-2b) + (-4c) ] × [ a² + (-2b)² + (-4c)² -a (-2b)-(-2b) (-4c) -a(-4c) ]

    ⇒ (a-2b-4c)(a²+4b²+16c²+2ab-8bc+4ac).

     

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